5^2x+1=28(5^x-1)

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Solution for 5^2x+1=28(5^x-1) equation: 



5^2x+1=28(5^x-1)

We move all terms to the left:

5^2x+1-(28(5^x-1))=0



We calculate terms in parentheses: -(28(5^x-1)), so:

28(5^x-1)

We multiply parentheses

140x-28

Back to the equation:

-(140x-28)



We get rid of parentheses

5^2x-140x+28+1=0

We add all the numbers together, and all the variables

-140x+5^2x+29=0

We move all terms containing x to the left, all other terms to the right

-140x+5^2x=-29

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